14x^2-7x-49=-7

Solution for 14x^2-7x-49=-7 equation:

14x^2-7x-49=-7

We move all terms to the left:

14x^2-7x-49-(-7)=0

We add all the numbers together, and all the variables

14x^2-7x-42=0

a = 14; b = -7; c = -42;
Δ = b2-4ac
Δ = -72-4·14·(-42)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-49}{2*14}=\frac{-42}{28}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+49}{2*14}=\frac{56}{28}
=2
$